[Fixed] JSON parse error: Cannot deserialize value of type from Array value (token `JsonToken.START_ARRAY`) – Java

by
Ali Hasan
cucumber-java mysql-connector-python spring-boot spring-data-jpa spring-mvc

Quick Fix: Remove the square brackets ([]) from your request body. These brackets indicate that the data you are transmitting is an array, which may not be compatible with the JSON parser.

The Problem:

When attempting to deserialize JSON data into a Java object using Jackson, an error occurs indicating that the JSON value cannot be deserialized from an array (token ‘JsonToken.START_ARRAY’). This error typically occurs when the expected JSON structure is an object but the actual JSON data is an array.

The Solutions:

Solution 1: Remove Array Syntax

The JSON error indicates a mismatch between the expected data type (an object) and the received data type (an array). To resolve this issue, remove the square brackets ([]) from your request body, as they indicate that the data is an array.

Before:

{
  "field1": [
    "value1"
  ],
  "field2": [
    "value2"
  ]
}

After:

{
  "field1": "value1",
  "field2": "value2"
}

By removing the array syntax, you are sending an object with key-value pairs, which is the correct format for your request.

Q&A

What is causing this JSON parse error?

The JSON is an array, but the code expects a single object.

How to fix this JSON parse error?

Remove the square brackets from the JSON to make it a single object.

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